0=16t^2+32t+5.2

Solution for 0=16t^2+32t+5.2 equation:

0=16t^2+32t+5.2

We move all terms to the left:

0-(16t^2+32t+5.2)=0

We add all the numbers together, and all the variables

-(16t^2+32t+5.2)=0

We get rid of parentheses

-16t^2-32t-5.2=0

a = -16; b = -32; c = -5.2;
Δ = b2-4ac
Δ = -322-4·(-16)·(-5.2)
Δ = 691.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-\sqrt{691.2}}{2*-16}=\frac{32-\sqrt{691.2}}{-32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+\sqrt{691.2}}{2*-16}=\frac{32+\sqrt{691.2}}{-32}
$